Problem
Three dinos go on a camping trip. There they decide to play a game. They mark distances of 1 km each on the ground up to 100 km i.e. 1, 2, 3…100. They can sit only on these 100 spots, with each one at a different spot. In one move, one of the outer dinos can hop into a spot between the other two. Help them maximise their duration of play.
Input
Three numbers(integers), l, m and n (0 < l < m < n < 100), the starting spots of the dinosaurs.
Output
Output the largest number of jumps the dinosaurs can make in all.
Constraints
- 0 < l < m < n < 100
Sample Input
5 6 11
Sample Output
4
Solution
Greedy Approach: Choose the maximum distance between the dinosaurs among 1st & 2nd and 2nd & 3rd.
Code Implementation
//
// main.cpp
// Jump it up
//
// Created by Himanshu on 16/04/22.
//
#include <iostream>
using namespace std;
int main() {
int a, b, c;
cin>>a>>b>>c;
if ((b-a)>(c-b)) {
cout<<(b-a-1)<<endl;
} else {
cout<<(c-b-1)<<endl;
}
return 0;
}
Time Complexity: O(1)